(4x^2-1)/(2x-1)=9

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Solution for (4x^2-1)/(2x-1)=9 equation:


D( x )

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

(4*x^2-1)/(2*x-1) = 9 // - 9

(4*x^2-1)/(2*x-1)-9 = 0

(4*x^2-1)/(2*x-1)+(-9*(2*x-1))/(2*x-1) = 0

4*x^2-9*(2*x-1)-1 = 0

4*x^2-18*x+8 = 0

4*x^2-18*x+8 = 0

2*(2*x^2-9*x+4) = 0

2*x^2-9*x+4 = 0

DELTA = (-9)^2-(2*4*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+9)/(2*2) or x = (9-49^(1/2))/(2*2)

x = 4 or x = 1/2

2*(x-1/2)*(x-4) = 0

(2*(x-1/2)*(x-4))/(2*x-1) = 0

(2*(x-1/2)*(x-4))/(2*x-1) = 0 // * 2*x-1

2*(x-1/2)*(x-4) = 0

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 1/2}

x = 4

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